How to translate this example in C++ and Python?

Question

I write a little article where I would like to show how the same code looks in different languages. To avoid accusations that one of the languages of poorly written code, I want to ask to help me translate the following sample code in D for C++ and Python. Need analog functionality 1k1.

import std.algorithm, std.stdio, std.string;
// Count words in a file using ranges.
void main()
{
    auto file = File("file.txt"); // Open for reading
    const wordCount = file.byLine()            // Read lines
                          .map!split           // Split into words
                          .map!(a => a.length) // Count words per line
                          .sum();              // Total word count
    writeln(wordCount);
}

Here is the second code snippet (castest counts the repetition of words):

import std.stdio, std.string; 

void main() { 
    uint[string] dictionary; 
    foreach (line; File("example.txt").byLine()) { 
    // Break sentence into words 
    // Add each word in the sentence to the vocabulary 
    foreach (word; splitter(strip(line))) { 
        if (word in dictionary) continue; // Nothing to do 
        auto newlD = dictionary.length; 
        dictionary[word] = newlD; 
        writeln(newlD, '\t', word);
        }
    }
}

If you can also comment on each line.

Answer 1

Python

total = 0
f = open('file.txt')
for line in f.readlines():
    total += len(line.split())

print total

with open('file.txt') as f:
    print len(f.read().split())

Answer 2

The canonical code that is closer to your code than the version from Andrey :

with open('test.txt', 'r') as f:
    print(sum(len(line.split()) for line in f.readlines()))

And it is just like you:

with open('test.txt', 'r') as f:
    print(sum(map(len, map(str.split, f.readlines()))))

The second task:

# печатаем уникальные слова(ваш вариант с ошибкой)
with open('test.txt', 'r') as f:
    for word in set(word.strip() for word in f.read().split()):
        print(word)


# выводим слова и их количество(то, что вы подразумавали)
from collections import defaultdict # словарь, для которого можно указать значения по умолчанию

with open('test.txt', 'r') as f:
    words = defaultdict(int) # функция, вызывающаяся для каждого нового ключа, int() возвращает 0

    for word in (word.strip() for word in f.read().split()):
        words[word] += 1 # можно не проверять на наличие ключа, а сразу инкрементировать, т.к. значение по умолчанию - 0

    for word, num in words.items():
        print(word, '\t', num)

Comments

Ah Yes, it's Python 3, and in the two most also